M<GFN = 4x+10, m<NFE = 14x + 3, and m<3GFE = 157°. find m<NFE
1 answer:
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Answer:
a) 11.40% probability of 5 bits being in error during the transmission of 1 kb
b) 11.60% probability of 8 bits being in error during the transmission of 2 kb
c) 0.01% probability of no error bits in 3kb
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the giveninterval.
Poisson distribution with mean of 3.2 bits/kb (per kilobyte).
This means that , in which kb is the number of kilobytes.
(a) What is the probability of 5 bits being in error during the transmission of 1 kb?
This is P(X = 5) when
11.40% probability of 5 bits being in error during the transmission of 1 kb
(b) What is the probability of 8 bits being in error during the transmission of 2 kb?
This is P(X = 8) when
11.60% probability of 8 bits being in error during the transmission of 2 kb
(c) What is the probability of no error bits in 3kb?
This is P(X = 0) when
Then
0.01% probability of no error bits in 3kb