Answer:
Step-by-step explanation:
f(x) = 3(x + 4)(x – i)(x + i)(x – 2)
Answer: x^3z/3 is your answer
Step-by-step explanation:
The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
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(4 2/3) / (4 1/5) = 1.111
The answer would be B. You multiply the 2 on both sides, getting 12 on the right. Then you divide by -1, and that switches the sign and makes 12 negative.