Side AB is 18, Side AC is 9, Side BC is 5. Find the SinA. Give your answer in fraction and decimal form.

Mathematics

1 answer:

Sladkaya [172]1 year ago

7 0

Input data

In any right triangle, the sine of an angle x is the length of the opposite side (O) divided by the length of the hypotenuse (H). In a formula, it is written as 'sin' without the 'e':

$\begin{gathered} \sin A=\frac{5}{18} \\ \sin A=0.277 \end{gathered}$

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Answer:

$7\frac{1}{4} -2\frac{5}{12} =\frac{58}{12} =4\frac{10}{12}$

Step-by-step explanation:

Given:

$7\frac{1}{4} =\frac{7\times 4 +1}{4}=\frac{29}{4}$

$2\frac{5}{12}=\frac{12\times 2+5}{12}=\frac{29}{12}$

To Find:

$7\frac{1}{4} -2\frac{5}{12} =?$

Solution

Substituting the above values we get

$7\frac{1}{4} -2\frac{5}{12} =\frac{29}{4} -\frac{29}{12}$

Now make both the denominator same by multiplying and dividing by 3 to the first term so we get

$7\frac{1}{4} -2\frac{5}{12} =\frac{29\times 3}{4\times 3} -\frac{29}{12}\\\\7\frac{1}{4} -2\frac{5}{12} =\frac{87}{12} -\frac{29}{12}\\\\7\frac{1}{4} -2\frac{5}{12} =\frac{87-29}{12}\\\\7\frac{1}{4} -2\frac{5}{12} =\frac{58}{12} =4\frac{10}{12}$