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3 years ago

Running out of time. Please make sure you know how to do this. Can't miss too many more!!!!!

Mathematics

2 answers:

oee [108]3 years ago

4 0

Answer:

its the second one

Step-by-step explanation:

lina2011 [118]3 years ago

3 0

Answer:

∠ 3 and ∠ 2

Step-by-step explanation:

Complementary angles sum to 90°

Since ∠ 1 = 90° and ∠ 1, ∠ 2 and ∠3 lie on a straight line, then

∠ 1 + ∠ 2 + ∠ 3 = 180°, that is

90° + ∠ 2 + ∠ 3 = 180° ( subtract 90° from both sides )

∠ 2 and ∠ 3 = 90°

Since they sum to 90° then

∠ 3 and ∠ 2 are complementary

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What is the degree of this polynomial 15x^5z^2-7y

Tanya [424]

That polynomial is made up of 2 terms, $15 x^{5}z ^{2}$ and 7y, separated by a minus sign. To find the degree of a polynomial you consider the term with the highest degree, no matter that the variables are different. The degree on the first term is 5+2=7, whereas the degree on the second term is just 1. Since the degree of a polynomial is equal to the degree of the term that is highest, our degree is 7.

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3 years ago

What is the value of x? please help me! A. 43 B. 62 C. 105 D. 115

Valentin [98]

Answer:

Step-by-step explanation:

x is the exterior angle of angle EFG while EFG = 180 - 62 - 43 = 75

—> x = 180 - 75 = 105

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2 years ago

F(-12) if f(x) = 2x + 15

Alenkinab [10]

Answer: $f(-12)=-9$

Step-by-step explanation:

We have the following function:

$f(x)=2x+15$

And we have to evaluate it when $x=-12$ , this means we have to substitute $x$ by $-12$ :

$f(-12)=2(-12)+15$

Solving:

$f(-12)=-24+15$

Finally:

$f(-12)=-9$

8 0

4 years ago

The freshman class will be selling carnations as a class project. What is the class's income after it pays the florist a flat fe

mr Goodwill [35]

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3 years ago

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bazaltina [42]

Answer:

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Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .