The last statement is true
Y^2 = (2x+1)/(x-1)
xy^2-y^2 = 2x + 1
xy^2 - 2x = y^2 + 1
x(y^2 - 2) = y^2 + 1
x = (y^2 + 1) / (y^2 - 2)
Answer:
Option B
Step-by-step explanation:
Find the zeros of each factor thus,
4x+3=0
x=-¾
And x-6=0
x=6
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I think the answer would be 41.28