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Angelina_Jolie [31]
3 years ago
13

7. Question Category: Solving Quadratic Equations by Factoring Select the correct answer. Solve the following quadratic equation

. (4x + 3)(x- 6)=0
A) x = -6, 3/4
B) x = -3/4, 6
C) x = 4/3, 6
D) x= - 3, 3/2
Mathematics
1 answer:
Alona [7]3 years ago
7 0

Answer:

Option B

Step-by-step explanation:

Find the zeros of each factor thus,

4x+3=0

x=-¾

And x-6=0

x=6

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Math question screen shot down below
Oksanka [162]

Answer:

The correct answer is A, Point P

Step-by-step explanation:

since the additive inverse of 2 is -2 because -2 + 2 = 0 the correct choice must be choice A, Point P.

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3 years ago
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Consider the vector b⃗ b→b_vec with length 4.00 mm at an angle 23.5∘∘ north of east. What is the y component bybyb_y of this vec
Stells [14]

Answer:

  • \large\boxed {1.59 mm}

Explanation:

<u>1. Given vector:</u>

  • length: 4.00 mm = magnitude of the vector
  • angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)

<u>2. y-component</u>

The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.

  • sine (23.5º) = y-component / magnitude

  • y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.

  • \large\boxed{y-component = 1.59 mm}

7 0
3 years ago
The starting and stopping point for Amir’s run this morning are 0.5 inch apart on the map. If each inch on the map represents 3
Aleonysh [2.5K]
Amir ran 1.5 miles in the morning.
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3 years ago
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surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo
balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

Tan(58°)*100m = h1 = 160m.

The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be:

h2 - h1 =  196.3m -  160m = 36.3m

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3 years ago
The diagram below is divided into equal parts. Which shows the ratio of unshaded section to shaded sections
xxTIMURxx [149]

Answer:

<u>its D</u>

Step-by-step explanation:

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