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Katena32 [7]
3 years ago
12

How to solve problems with the distrbutive property with variables?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0
To solve if the number inside the parantaces have a virable then you will multiply it for example 4(a+2) you would multiply 4*a=4a 4*2=8 and your answer will be 4a+2
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Match the base to the corresponding height.
Sergio039 [100]

The first base matches the second height

The second base matches the first height

The third base matches the third height

<h3>Base and height of a triangle  </h3>

From the question, we are to match the base to the corresponding height

In a triangle, the height of the triangle is perpendicular to the base.

Applying this in the given diagram,

The first base matches the second height

The second base matches the first height

The third base matches the third height

Learn more on Base and height of a triangle here: brainly.com/question/17154315

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5 0
2 years ago
This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
3 years ago
Plzzzz help I'll fail unless I get this in 6 minutes. Will give BRAINLIEST to answer!!!!!!
raketka [301]

Answer:

What is the question

Step-by-step explanation:

8 0
3 years ago
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