The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
Answer:
2km/m
Step-by-step explanation:
6 laps = 10km
(because 3 x 2 = 6 and double 5km as well)
Distance divide time = speed
20 mins divided by 10km = 2km per minute
Statement: 1) Triangle ABC
2) 2x 3)x=52
Reason: I’m not sure but probably addition
4^-3
You first need to make the exponent positive. To do this put it in a fraction.
1/4^3
Now solve the exponent.
4 * 4 * 4 =
^
16*4 = 64
1/64 is your answer
Answer:
35/8
Step-by-step explanation:
1 3/4 = 1 + 3/4 = 4/4 + 3/4 = 7/4.
So 1 3/4 ÷ 2/5 = 7/4 × 5/2 = 35/8.
