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Natasha_Volkova [10]
2 years ago
13

It cost the company $0.20 to make a box of mints. If the company sells each box for $3, and it’s total yearly profit is $280,000

, how many boxes of mints does the company sell each year?
Mathematics
1 answer:
baherus [9]2 years ago
5 0

Answer:

they sell 100,000 each year

Step-by-step explanation:

since it takes $0.20 to make a box, you subtract it from $3, meaning that they make a profit of $2.80 for each box, now you divide $280,000 by $2.80 which is 100,000

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stiks02 [169]

☁️ Answer ☁️

5. IS E (none of these)

Because I got:

-125y^5/162x

6. X = 5/3

Hope it helps.

Have a nice day noona/hyung.

7 0
2 years ago
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Help? I'd Appreciate it!
kondor19780726 [428]

<u>Answer</u>

y = (1/2)x - 1


<u>Explanation</u>

The first step is to get the gradient of the line.

The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

                = -2/-4

                 = 1/2

To get the function we use one of the point (2,0) and a general point (x,y).

1/2 = (y - 0)/(x - 2)

1/2 = y/(x - 2)

(x - 2) = 2y

2y = x - 2

y = (1/2)x - 1

8 0
3 years ago
What is the y intercept? f(x)=-2^2+4x-6
den301095 [7]

Answer:

The y intercept is -1

Step-by-step explanation:

the y-intercept is when y = 0

f(0) = -2^2 + 4(0) - 5

f(0) = 4 - 5

f(0) = -1

8 0
3 years ago
Triangle ABC is translated using the rule (x, y) → (x + 1, y − 4) to create triangle A′B′C′. If a line segment is drawn from poi
nalin [4]

Answer:

The line segments AA' and BB' are parallel and congruent

Step-by-step explanation:

4 0
2 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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