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Tju [1.3M]
3 years ago
14

Eva draws a line that includes the points (2,0) and (-2,2). Which function gives all the

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

y= -1/2x +1

Step-by-step explanation:

use the slope equation to find the slope, and the the point slope equation to solve for your equation

strojnjashka [21]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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NOT A SCAM..... PLEASE HELP MEMEEEEEEEEEEEEEE
umka21 [38]

Answer:

(3, 0).

Step-by-step explanation:

dentifying the vertices of the feasible region. Graphing is often a good way to do it, or you can solve the equations pairwise to identify the x- and y-values that are at the limits of the region.

In the attached graph, the solution spaces of the last two constraints are shown in red and blue, and their overlap is shown in purple. Hence the vertices of the feasible region are the vertices of the purple area: (0, 0), (0, 1), (1.5, 1.5), and (3, 0).

The signs of the variables in the contraint function (+ for x, - for y) tell you that to maximize C, you want to make y as small as possible, while making x as large as possible at the same time.

Hence, The Answer is ( 3, 0)

3 0
3 years ago
Read 2 more answers
Find the smallest solution to the equation 2/3 x^2 =24
lesya692 [45]

Answer:

\frac{2x^2}{3} =24

Step-by-step explanation:

times both sides by 3

2x²=72

divide both sides by 2

x²=36

sqrt both sides

x=+/-6

x=-6 or 6

-6<6 so -6 is the smallest solution

7 0
3 years ago
Solve y = x - 5 if the domain is 5
Lunna [17]
If the domain is 5, you just put that five where you find an x. So,
y = 5 - 5
y = 0

Domain means those are the numbers that will be set as x's in the equation
6 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
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