What is the vertical asymptote

Mathematics

2 answers:

Marta_Voda [28]3 years ago

4 0

Answer: the red lines

ad-work [718]3 years ago

3 0

Answer:

x =-6

and y axis or x = 0

i hope you will like my answer

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An airplane was cruising at 23,000 feet altitude. Due to turbulence it dropped 4,300 feet.Once the air currents leveled off he w

vladimir1956 [14]

Answer:

-700 feet, aka 700 feet below/away from the original cruising altitude

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3 years ago

Monica has walked 3/2 miles in 2/3 of an hour. How many miles can Monica walk in one hour?

defon

Answer:

2.25 Miles is how many miles Monica can walk in one hour.

Step-by-step explanation:

You take 3/2 which is 1.5 in decimal form then take the 2 out of 2/3 divide 1.5 by 2, you get 0.75 then you add 0.75 to 1.5 and you get 2.25 which is how many miles she walks in one hour.

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2 years ago

Read 2 more answers

In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°