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choli [55]
3 years ago
12

HELP PLS

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

<em>Thus the domain is the real numbers and the range is y>3.</em>

<em>Answer: Option C)</em>

Step-by-step explanation:

<u>Domain and Range of Functions</u>

To determine the domain and range of a function given on a graph, we use the vertical and horizontal line methods respectively.

The domain consists of all the values of x for which the function exists. We are told that the function is an exponential decay. Exponential functions without specified restrictions have a domain of all the real numbers.

Imagine a vertical line moving from minus infinite x to plus infinite. The line would always cross the graph at one point, thus the domain is all the real numbers.

Now for the range, imagine a horizontal line coming from y minus infinite. It won't get in contact with the graph until it approaches y=3. Once it goes up y=3, the line touches the graph in one point up to infinity y. The range is y>3.

Thus the domain is the real numbers and the range is y>3.

Answer: Option C)

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Vsevolod [243]

Answer:

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= ( - 4) \times (2) + 2

=  - 8 + 2

=  - 6

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What is the GCF of h4 and h8
masha68 [24]

Answer:

gcf is h4 or just 4

Step-by-step explanation:

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4 years ago
.A straight line passes through point A(2,4) and B(6,12). Find the equation of the perpendicular bisector of line AB (write your
sergiy2304 [10]

Answer:

x + 2y = 20

Step-by-step explanation:

We require the slope and the midpoint of AB

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = A(2, 4) and (x₂, y₂ ) = B(6, 12)

m = \frac{12-4}{6-2} = \frac{8}{4} = 2

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{2}

-----------------------------------

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} ]

Thus midpoint of AB = ( \frac{2+6}{2}, \frac{4+12}{2} ) = (4, 8 )

--------------------------------------------

y = - \frac{1}{2} x + c ← partial equation of perpendicular bisector

To find c substitute (4, 8) into the partial equation

8 = - 2 + c ⇒ c = 8 + 2 = 10

y = - \frac{1}{2} x + 10 ← in slope- intercept form

Multiply through by 2

2y = - x + 20 ( add x to both sides )

x + 2y = 20 ← in the form ax + by = c

7 0
4 years ago
What is the area of a rectangle with length 1/12 ft and width 3/4 ft
Mila [183]

Answer:

3/48 or reduced 1/16

Step-by-step explanation:

1/3 x 3/4 = 3/48

Reduced:

3/48 ÷ 3/3 = 1/16

Only put the reduced fraction if it asks.

Hope this helps :)

7 0
4 years ago
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