Answer:
225 rs
Step-by-step explanation:
cost of 1 pen = 20 rs
total cost of 4 pens = 20×4= 80 rs
cost of 1 pencil = 5 rs
total cost of 5 pencils = 5×5 = 25 rs
cost of 1 box = 60 rs
total cost of 2 boxes = 60×2 = 120 rs
Total= 80+25+120 = 225 rs
Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Answer: 
Step-by-step explanation:
Given: The factory produces equal quantities of four flavors cherry lemon orange and strawberry.
Let orange candy= cherry = lemon = strawberry = x
Total candies = x + x + x + x= 4x
The probability that a randomly selected candy is orange = 
Hence, the probability that a randomly selected candy is orange = 
Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
im gonna say 23 or 24 not 100% sure
Step-by-step explanation: