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Oxana [17]
3 years ago
9

PLEASE HELP ME BRAINLIEST TO RIGHT ANSWER

Mathematics
2 answers:
N76 [4]3 years ago
3 0

Can you put it in any form instead of a point so I can correctly plot it in

Andrews [41]3 years ago
3 0
I’m guessing (-10,-2) not entirely sure. Let me know if this is the right or wrong answer
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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
Find the slope of the line containing the points (3,-2) and (-1,6)​
dezoksy [38]

Answer: the answer is -2

Step-by-step explanation: use slope formula

3 0
4 years ago
Read 2 more answers
Please help, I will give brainliest, I am struggling badly.
Alja [10]

Answer:

Step-by-step explanation:

Notice they both have the same slope of 3x so they are parallel, but different y intercepts. This means the lines never intersect and thus there are no solutions to the system of equations.

3 0
3 years ago
Read 2 more answers
Donna rented a truck for one day. There was a base fee of $14.00, and there was an additional charge of 25 cents for each mile d
Akimi4 [234]
The answer is $21.50
7 0
3 years ago
The sum of two numbers is 80 If four times the smaller number is subtracted from the larger number, the result is 10. Find the t
timama [110]
This can be solved using a system of equations. 
\left \{ {{x+y=80} \atop {x-4y=10} \right. &#10;
Subtract y from both sides.
x=80-y
Substitute:
80-y-4y=80-5y=10
Subtract 80 from both sides:
5y=70
Divide both sides by 5:
y= \frac{70}{5} =14
Substitute.
x=80-14=66
3 0
3 years ago
Read 2 more answers
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