Question

Hi guys I need your help here I'll give 100 points and also brainiest no link's please I need this by today thank you : )​

Answer 1

Answer:

#2

CD  ║ EF and ED is transversal, hence

• ∠CDE ≅ ∠FED ⇒ m∠CDE = m∠FED ⇒ m∠CDE = 28° as alternate interior angles

• m∠CDB = 160° - 28° = 132°

We can see that:

• m∠CDB + m∠ABD = 132° + 48° = 180°

Since the angles CDB and ADB sum to 180, these are consecutive interior angles, therefore AB and CD are parallel lines.

#3

PU and QT are parallel and PT is transversal, therefore:

• ∠UPT ≅ ∠QTP as alternate interior angles

• m∠UPT = m∠QTP = 42° or x = 42°

Now find the missing angles of ΔQTP

• x + 40° = 42° + 40° = 82°
• y = 180° - (42° + 82°) = 56°

Now, we see that:

• m∠TPQ = 82°
• m∠SQR = 82°

As  ∠TPQ ≅ ∠SQR  these angles are corresponding angles.

Therefore PT and SQ are parallel lines.