The solution would be like this for this specific problem:
H0: p = p0, or <span>
H0: p ≥ p0, or
H0: p ≤ p0 </span>
find the test statistic z
= (pHat - p0) / sqrt(p0 * (1-p0) / n)
where pHat = X / n
The p-value of the test is
the area under the normal curve that is in agreement with the alternate
hypothesis. <span>
H1: p ≠ p0; p-value is the area in the tails greater than |z|
H1: p < p0; p-value is the area to the left of z
H1: p > p0; p-value is the area to the right of z </span>
Hypothesis equation:
H0: p ≥ 0.67 vs. H1: p
< 0.67
The test statistic is: <span>
z = ( 0.5526316 - 0.67 ) / ( √ ( 0.67 * (1 - 0.67 ) / 38 )
z = -1.538681 </span>
The p-value = P( Z < z
) <span>
= P( Z < -1.538681 )
<span>= 0.0619</span></span>
Answer:
28% She didn't make a profit over 30%
Step-by-step explanation:
She buys the clocks for 50 pounds
She sells them for 22 + 22 + 20 = 64 pounds.
The profit is 14 pounds
What's the % profit.
Profit % = 14/50*100 = 28%
She's not quite right.
To simplify ![\frac{3}{\sqrt[3]{3} }](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B%5Csqrt%5B3%5D%7B3%7D%20%7D)
, we have to follow the rules.
Here are the steps to the question:
Step 1: Follow the radical rule.
![\sqrt[n]{a}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D)
= a 
So, we get 
.
Next, follow the exponent rule.
= 
We get 
.
The answer is \frac{3}{\sqrt[3]{3} }.
6 2/3 = 20/3 = 60/9
4 4/9 = 40/9
60/9 - 40/9 = 20/9 = 2 2/9
