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stealth61 [152]
2 years ago
6

Which equation can be used to solve 3a = 15?

Mathematics
2 answers:
Zina [86]2 years ago
7 0
The is answer is A 15/3 which can be used to solve 3a= 15
Hoochie [10]2 years ago
6 0

Answer: a

Explanation:

3a=15 is the same thing as the expression 15 divided by 3

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10 gallons and 11 quarts divided by 3
ivanzaharov [21]
4 quarts per gallon 
<span>10 gallons: 4x10 = 40 quarts. </span>
<span>Add the 11 quarts to get 51 quarts. </span>
<span>51 divided by 3 = 17 quarts, or 4 gallons + 1 quart.</span>
5 0
3 years ago
Read 2 more answers
Find the volume of the cylinder. Use pi = 3.14* the height of 6 inches and a radius 4.5in​
ArbitrLikvidat [17]

Answer: 381.51 cubic inches

Step-by-step explanation:

1. Use the formula: V = πr^{2}h, or in this case, 3.14(4.5^{2})(6)

2. Simplify to 3.14(20.25)(6)

3. Simply multiply all three numbers using a calculator, or one by one if that's the preferred option.

4. You get: 381.51 cubic inches.

8 0
3 years ago
Suppose a coin is flipped and a card is drawn from the deck. What is the probability that the coin lands on tails and the card i
Deffense [45]

Answer:

1/26

Step-by-step explanation:

1 out of 13 would be equal to the amount of cards that would be a jack.

But you also have to take into regards the coin flip 50%chance so you would just could what the number is divided by to get the right answer. Since out come could be tails or head instead of just being one for sure for example.

5 0
3 years ago
Evaluate the following trigonometric expression
Harlamova29_29 [7]

Answer:

-60

hope it helps

5 0
2 years ago
The average of A and B is 6. The average of X, Y, and Z is 16. What is the average of A, B, X, Y, and Z?
ser-zykov [4K]

Answer:

12

Step-by-step explanation:

Average of A and B is 6

(A+B) /2 = 6

Multiply each side by 2

A+B = 12

average of X, Y, and Z is 16

(X+Y+Z)/3 = 16

Multiply each side by 3

(X+Y+Z) = 48

To find the average of all of them

(A+B+X+Y+Z)/5

replace A+B with 12 and X+Y+Z with 48

(12+48)/5

60/5 = 12

4 0
3 years ago
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