Answer:
11/3 = 3 2/3 ≈ 3.66667
Step-by-step explanation:
The external angle is half the difference of the intercepted arcs:
3x = (1/2)((9x +25) -36)
6x = 9x -11
11 = 3x . . . . . . . add 11-6x
11/3 = x
_____
The attached figure is drawn to scale.
A right angled triangle has sides of length 9cm, 12cm and 15cm. Calculate its area in square centimetres.
1 answer:
The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.
The formula to calculate the area of a right triangle is given by:
Area of Right Triangle, A = (½) × b × h square units
Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.
We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.
Given sides of the triangle:
a=9cm
b=12cm
c=15cm
From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.
∴Area = x 9 x 12
= 54
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9 Ibs(pounds) + 6 oz(ounces) ⇒ ounces
First, let's find out how many 1 pound is equal to in ounces.
Since 1 pound is equal to 16 ounces, multiply the 9 pounds by 16.
Now, add the remaining 6 ounces to 144 ounces, which is also 9 pounds.
The answer is 150 ounces.
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