Please could someone help with this ? Thankyou
2 answers:
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We can solve this problem using the binomial distribution. A binomial distribution<span> can be thought of as a success or failure outcome in an experiment or survey that is repeated multiple times.
</span>Probability function of binomial distribution has the following form:
p represents the probability of each choice we want. k is the number of choices we want and n is the total number of choices.
In our case p=0.85, k=5 and n=6.
We can now calculate the answer:
The probability is 39%.
.
</span>Probability function of binomial distribution has the following form:
p represents the probability of each choice we want. k is the number of choices we want and n is the total number of choices.
In our case p=0.85, k=5 and n=6.
We can now calculate the answer:
The probability is 39%.
.
Answer:
The degrees of freedom are given by:
The p value wuld be given by:
For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40
The distribution with the critical values are in the figure attached
Step-by-step explanation:
Information given
48, 41, 40, 51, and 50
The sample mean and deviation can be calculated with these formulas:
represent the mean height for the sample
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test
Hypothesis to test
We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing we got:
The degrees of freedom are given by:
The p value wuld be given by:
For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40
The distribution with the critical values are in the figure attached
