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Marrrta [24]
3 years ago
8

A runner increases his velocity from 0 m/s to 20 m/s in 2.0s. What was his average acceleration?

Mathematics
1 answer:
xenn [34]3 years ago
7 0

change in velocity = 20 - 0 = 20

change in time = 2 seconds

Divide the change in velocity over the change in time: 20/2 = 10

The average acceleration is 10 m/s^2

I.e, each second, the speed increases by 10 m/s

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\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}

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  • <u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

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  • <u>Solution</u><u> </u><u>:</u><u>-</u>

<em>We</em><em> </em><em>know</em><em> </em><em>that</em>

<em>\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }</em>

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<em>\sf  \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\  \\  \\  \sf \longmapsto perimeter = 2 \{3x + 10 \} \\  \\  \\  \sf  \longmapsto perimeter = 6x + 20</em>

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