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patriot [66]
3 years ago
12

: Maria attended a Chicago Cubs baseball game last night. The ticket to get into the game was $39.00 and hot dogs cost $5.50 eac

h. Maria had at most $60 to spend for a ticket and as many hot dogs she could buy without overspending. What is the most number of hot dogs Maria could buy at the baseball game without overspending?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer: 3

Step-by-step explanation:

At first you would subtract 39 from 60. Then you would do 21/5.5 and you would get 3.818… and due to the fact you can't go over 60 you would round to 3 and not 4

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nikitadnepr [17]
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MissTica
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thus \bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1r^{n-1}\qquad &#10;\begin{cases}&#10;a_1=\textit{first term}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2(-4)^{n-1}
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