2 years ago

Find x. I need help please

Mathematics

1 answer:

Misha Larkins [42]2 years ago

3 0

Answer:

$x = 4 \sqrt{3}$

Step-by-step explanation:

By geometric mean theorem and Pythagoras theorem:

${x}^{2} = { (\sqrt{8 \times 4} )}^{2} + {4}^{2} \\ \\ {x}^{2} = { (\sqrt{32} )}^{2} + {4}^{2} \\ \\ {x}^{2} = 32 + 16 \\ \\ {x}^{2} = 48 \\ \\ x = \sqrt{48} \\ \\ x = 4 \sqrt{3}$

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