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alexdok [17]
3 years ago
14

Find x. I need help please

Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

x = 4 \sqrt{3}

Step-by-step explanation:

By geometric mean theorem and Pythagoras theorem:

{x}^{2}  =  { (\sqrt{8 \times 4}  )}^{2} +  {4}^{2}  \\  \\  {x}^{2}  =  { (\sqrt{32}  )}^{2} +  {4}^{2}  \\  \\  {x}^{2}  =  32 + 16 \\  \\  {x}^{2}  = 48 \\  \\ x =  \sqrt{48}  \\  \\ x = 4 \sqrt{3}

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