Use the following isosceles triangle to find valur of x and the length of ac.

1 answer:

3 0

Given that the triangle is isosceles, we can say that AB = AC. Using the given expressions we can form the following equation.

$\begin{gathered} AB=AC \\ 5x+8=7x-6 \end{gathered}$

Let's solve for x.

$\begin{gathered} 8+6=7x-5x \\ 14=2x \\ x=\frac{14}{2} \\ x=7 \end{gathered}$

Once we have the value of the variable, we can find the length of AC.

$\begin{gathered} AC=7x-6 \\ AC=7(7)-6 \\ AC=49-6 \\ AC=43 \end{gathered}$ <h2>Therefore, the length of AC is 43.</h2>

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A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round

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Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 137, \sigma = 7$