Answer:
27:9:9:9:3:3:3:1
Explanation:
The gametes of the parental genotypes would be  
ABC, ABc, AbC, aBC, Abc, aBc, abC, abc
The cross between AaBbCc and AaBbCc will result into following offspring  (image is also attached)
         ABC        ABc           AbC   aBC         Abc     aBc	abC	abc
ABC	AABBCC       AABBCc	AABbCC   AaBBCC	AABbCc	AaBBCc	AaBbCC	AaBbCc
ABc	AABBCc	AABBcc	AABbCc	AaBBCc	AaBbcc	AaBBcc	AaBbCc	AaBbcc
AbC	AABbCC	AABbCc	AAbbCC	AaBbCC	AAbbCc	AaBbCc	AabbCC	AabbCc
aBC	AaBBCC	AaBBCc	AaBbCC	aaBBCC	AaBbCc	aaBBCc	aaBbCC	aaBbCc
Abc	AABbCc	AABbcc	AAbbCc	AaBbCc	AAbbcc	AaBbcc	AabbCc	Aabbcc
aBc	AaBBCc	AaBBcc	AaBbCc	aaBBCc	AaBbcc	aaBBcc	aaBbCc	aaBbcc
abC	AaBbCC	AaBbCc	AabbCC	aaBbCC	AabbCc	aaBbCc	aabbCC	aabbCc
abc	AaBbCc	AaBbcc	AabbCc	aaBbCc	Aabbcc	aaBbcc	aabbCc	aabbcc
The genotype ratio is 27:9:9:9:3:3:3:1