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noname [10]
3 years ago
14

Help!! Whoever tries gets brainliest!

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0

Answer:

q: quarters, 2q, 2q + 22, & 3(2q+22)

Step-by-step explanation:

A: The variable “q” will be the number of quarters

B:

2q will be the numbers of dimes

2q+22 will be the numbers of nickels

3(2q + 22) will be th number of pennies

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Pls help....................
suter [353]

answer:

B

Step-by-step explanation:

   

6 0
3 years ago
Use the perimeter to find the length of segment AD. This is the distance from A to D. Explain how you found your answer. Please
jekas [21]

Answer:

AD = 5 units

Step-by-step explanation:

Given:

Perimeter = 18 units

BC = 4 units

CD = 3 units

Required:

Length of segment AD

Solution:

Perimeter = AB + BC + CD + AD

We can easily find AB,

AB = 6 units (distance from A to B)

Plug in the values

18 = 6 + 4 + 3 + AD

18 = 13 + AD

Subtract 13 from each side

18 - 13 = 13 + AD - 13

5 = AD

AD = 5 units

5 0
3 years ago
Brandon has a 15-year fixed rate mortgage for $175,000 with monthly payments of $1,480.97. The annual interest rate is 6%. What
mylen [45]
Amortization Solution:

A= P[[r(1+r)^n]/[((1+r)^n)-1)]]
P= $175,000
r= .06/12; divide interest rate by 12 to get monthly interest  of 0.005
n=15*12=180; multiply by 12 to get the total number of payments
A= $87500  is the total cost of principal with interest rate of 0.5% monthly
4 0
4 years ago
On a fair 6 sided number die: What is P( rolling an 8)
elena55 [62]

Answer:

There is no chance of rolling an 8

I hope this helps you. Let me know if I did this correctly.

7 0
4 years ago
The sum of two numbers is 52. One number is 3 times as large as the other number. Which is the larger number
creativ13 [48]

The two number are 39 and 13

<em><u>Solution:</u></em>

Let the two numbers be "a" and "b"

Let the larger number be "a" and the smaller number be "b"

<em><u>Given that, sum of two numbers is 52</u></em>

a + b = 52 ---------- eqn 1

<em><u>One number is 3 times as large as the other number</u></em>

Larger number = 3 times smaller number

a = 3b -------- eqn 2

<em><u>Let us solve eqn 1and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

3b + b = 52

4b = 52

b = 13

<em><u>Substitute b = 13 in eqn 2</u></em>

a = 3(13)

a = 39

Thus the two number are 39 and 13

4 0
3 years ago
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