<h2>Answer </h2>
Amount (A) = P[1 + (r/100)]n
Principal (P) = ₹ 26400
Time period (n) = 2 years 4 months
Rate % (R) = 15% compounded annually
<h3>Steps </h3>
First, we will calculate Compound Interest (C.I) for the period of 2 years
A = P[1 + (r/100)]n
= 26400[1 + (15/100)]²
= 26400[(100/100) + (15/100)]²
= 26400 × 115/100 × 115/100
= 26400 × 23/20 × 23/20
= 26400 × 1.3225
= 34914
C.I. = A - P
= 34914 - 26400
= 8514
Now, we will find Simple Interest (S.I) for the period of 4 months
Principal for 4 months after C.I. for 2 years = ₹ 34,914
<h3>We know that ,</h3>
S.I = PRT/100
Here T = 4 months = 4/12 years = 1/3 years
S.I. for 4 months = (1/3) × 34914 × (15/100)
= (1/3) × 34914 × (3/20)
= 34914/20
= 1745.70
Total interest for 2 years 4 months = 8514 + 1745.70
= 10259.70
Total amount for 2 years 4 months = 26400 + 10259.70
= ₹ 36659.70
<h3>
So , the correct answer is ₹ 36659.70 . </h3>
Answer:
1) 34 square meters
2) 21 square yards
Step-by-step explanation:
1) 7x4=28
1/2x3x2x2=6
28+6= 34 square meters
2)3x3=9
1/2x3x2x4=12
9+12= 21 square yards
Answer:
Yes
Step-by-step explanation:
One is in the hundreds and one is in the thousands. 100x10=1000
Answer:
The correct answer is 25.2 in.
Step-by-step explanation:
It is given that number line goes from 0 to 60 which can be used to represent a ribbon of length = 60 inches.
2 inches of the ribbon are frayed so actual length = 58 inches
Please refer to the attached image for the ribbon.
A is at 0
C is at 60
B is at 2
P is the point to divide the remaining ribbon in the ratio 2:3.
Part AB of the ribbon is frayed.
BP: PC = 2:3
Let BP = 2
and PC = 3
Now, BP + PC = BC = 58 = 2 + 3 = 5
So,
BP = 
Location of the Cut = 2 + 23.2 = <em>25.2 inches</em>
<em></em>
Alternatively, we can use the formula directly:
m: n is the ratio 2:3
Answer:
If he deposited weekly, he would be depositing 9 dollars each week.
Step-by-step explanation:
Just thank me later and click the crown at the top of this answer if it helped ;)
