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Ratling [72]
3 years ago
9

Find an equation of the line that has a slope of -8 and y-intercept of 6. Write the answer in the form Y = Mx+B

Mathematics
2 answers:
vova2212 [387]3 years ago
6 0
The answer to your question is y=8x+6
solong [7]3 years ago
3 0
The answer is y= -8x+6
-8 is the slope and 6 being the y-intercept.
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6:42 pm because you just subtract the elapsed time. 
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Nine square tiles are laid out on a table so that they make a solid pattern. perimeters of the fiques that you can be formed?
Anastasy [175]
Let the side of one square be x.
The maximum perimeter will be when the squares will be lined end to end.
This will be:
x + 9x + 9x + x
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The perimeter of the figures formed will be less than or equal to 20x.
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2 years ago
Consider the equation 2x+8y=12
rusak2 [61]
For a you have to solve 2 solutions , first 2x=12
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3 0
2 years ago
Please Help!!!!!!
navik [9.2K]

Answer:

6 team members

Step-by-step explanation:

We know that 2 team members can solve 13 problems in an hour. So, all you have to do is find what 195÷13 is, and multiply that by 2.

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And we have our answer!

I hope this helps! If it did, it would mean a lot to me if you could mark me brainliest :D

Have a nice day!

7 0
3 years ago
Read 2 more answers
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
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