Question

Please solve the equation below:

Answer 1

Answer:

$-20601101.006$

Step-by-step explanation:

$We\ are\ given:\\2\frac{3}{4}*2^4*42-32*2\frac{3}{10}*6^7+69+43*456 \div256+231-6^2\\By\ using\ the\ BEDMAS\ Order\ of\ Operations\ rule,\\Or,\\* Brackets-B\\*Exponents-E\\*Division-D\\*Multiplication-M\\*Addition-A\\*Subtraction-S$

$2\frac{3}{4}*2^4*42-32*2\frac{3}{10}*6^7+69+43*456 \div256+231-6^2\\Separating\ similar\ operations\ through\ brackets:\\=[2\frac{3}{4}*2^4*42]+[-32*2\frac{3}{10}*6^7]+[43*\frac{456}{256}]+[231-6^2+69]\\Simplifying\ mixed\ fractions\ and\ evaluating\ exponents:\\=[\frac{11}{4}*16*42]+[-32*\frac{23}{10}*279936]+[43*\frac{456}{256}]+[231-36+69]\\Evaluating\ terms\ inside\ the\ brackets:\\=[1848]+[-20603289.6]+[76.59375]+[264]\\Adding\ all\ the\ terms\ together:\\=-20601101.006 \approx -20601101$