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3 years ago

Hey Everyone Lets Party

Mathematics

2 answers:

Leviafan [203]3 years ago

7 0

Answer:

yessss bhett !!!!!! >.<

Step-by-step explanation:

djyliett [7]3 years ago

3 0

Answer:

WOOHOO

Step-by-step explanation:

YEAH BOII PARTYY!!

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Does anyone know how to do this? will give brainiest

lyudmila [28]

Answer:

x = 22, and im rlly sry, i dont know how to solve for y...im sry...

Step-by-step explanation:

180 - 55 = 125 degrees

6x - 7 = 125

+7 +7

6x = 132

divide by 6

x = 22

5 0

3 years ago

An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.

Lunna [17]

ANSWER

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

See attachment for the graph

EXPLANATION

The standard equation of the vertical ellipse with center at the origin is given by

$\frac{ {x}^{2} }{ {b}^{2} } + \frac{ {y}^{2} }{ {a}^{2} } = 1$

where

${a}^{2} \: > \: {b}^{2}$

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

${a}^{2} - {b}^{2} = {c}^{2}$

$\implies \: 289 - {b}^{2} = 225$

$- {b}^{2} = 225 - 289$

$- {b}^{2} = - 64$

${b}^{2} = 64$

We substitute into the formula for the standard equation to get:

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

4 0

3 years ago

Product of 3 x 2/3 is 3 true or false

Agata [3.3K]

True because it is hope it helps

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Simplify fully 2x(x+1)-3(x-5)

ser-zykov [4K]

2x(x+1)-3(x-5)

2x^2+2x-3x+15

2x^2-x+15

Answer: 2x^2-x+15

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4 years ago

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Anuta_ua [19.1K]

It’s should be the second on so b and you should get it corrdct

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