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Marysya12 [62]
3 years ago
10

Solve for x Y= x-v/b

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

x=y+v/b

Step-by-step explanation:

So first you have y=x-v/b. You want to isolate x, so subtract x from both sides. You'll get -x+y=-v/b. Next, you're going to want to subtract y to further isolate x now that it's on the left side. Now you'll have -x=-y-v/b. But you don't want x to be negative, so you can divide both sides by -1 to make x positive. Now you'll have x=y+v/b.

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Select the correct answer. Consider the following system of equations. Use this graph of the system to approximate its solution.
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The approximate solution to the given system of equations, considering the graph, is given as follows:

D. \left(-\frac{13}{4}, \frac{5}{2}\right).

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

On a graph, the solution of a system of equations is given by the intersection between the curves. In this graph, the intersection of the two curves happen close to x = -3.25, y = 2.5, hence the solution is approximated by:

D. \left(-\frac{13}{4}, \frac{5}{2}\right)

More can be learned about a system of equations at brainly.com/question/24342899

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It is A' B'

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Step-by-step explanation:

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\text{Hi there! :)}

\large\boxed{f'(2) = -\frac{16}{27} }

f'(x) = \frac{(5 + x^{2} )(-2x) - (7 - x^{2} )(2x)}{(5+x^{2})^{2}  } \\\\f'(x) = \frac{-10x-2x^{3}- 14x + 2x^{3} }{(5+x^{2})^{2} } \\\\f'(x) = \frac{-24x}{(5+x^{2})^{2}  }\\\\ \text{Solve for the derivative at f'(2) using substitution:}\\\\f'(2) = \frac{-24(2)}{(5+2^{2})^{2}   } \\\\f'(2) = \frac{-48}{81} \\\\\text{Simplify:}\\\\f'(2) = -\frac{16}{27}

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3 years ago
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