Check picture for question. (Geometry)

sharon serves the volleyball to rhonda with an upward velocity of 18.5 ft/s. The ball is 4.5 feet above the ground when she stri

andreyandreev [35.5K]

we can use height formula

$h(t)=-\frac{1}{2} g t^2+vt+h(0)$

where

h(t) is the height after t seconds

v is velocity

h(0) is initial height

g is acceleration due to gravity

we know that

g=32 ft/s^2

we have

v=18.5ft/s

h(0)=4.5ft

so, we can plug these values

and we get

$h(t)=-\frac{1}{2}*32 t^2+18.5t+4.5$

$h(t)=-16 t^2+18.5t+4.5$

now, we have to find time when object will hit the ground

and we know that object will hit the ground when height becomes 0

so, we can set h(t)=0

and then we can solve for t

$0=-16 t^2+18.5t+4.5$

we can use pythagoras theorem

$t=\frac{-185-\sqrt{185^2-4\left(-160\right)45}}{2\left(-160\right)}=\frac{37+\sqrt{2521}}{64}$

$t=1.36265sec$ ..............Answer

7 0

3 years ago

If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

Step-by-step explanation:

We have , $Tan\alpha = \frac{Perpendicular}{Base} = \frac{10}{13}$ ,

We know that $sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }$

Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

Now , $sin2\alpha = 2sin\alpha cos\alpha = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }$

⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{169 }{269} } )$

⇒ $sin2\alpha = \frac{260}{\sqrt{269} }( \sqrt{\frac{1}{269} } )$

⇒ $sin2\alpha = \frac{260}{269}$

6 0

3 years ago

B 20 A 19 С What is the length of BC?

vladimir2022 [97]

Answer:

6.245

Step-by-step explanation:

........... .....

4 0

3 years ago

3. Two numbers are in the ratio 3:5. If their difference is 12, what are the numbers?

vladimir2022 [97]

I got 18 and 30 for my answer

8 0

3 years ago

Which is the equation of a line that passes through the points (1,4) and (-1,1)

horsena [70]

Answer:

The equation of the line is y = 3/2x + 5/2

Step-by-step explanation:

To find the equation of this line, start by using the two points with the slope formula to find the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (4 - 1)/(1 - -1)

m = 3/(1 + 1)

m = 3/2

Now that we have the slope, we can use that and either point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 4 = 3/2(x - 1)

y - 4 = 3/2x - 3/2

y = 3/2x + 5/2

3 0

3 years ago