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nignag [31]
3 years ago
8

True/False; This table represents a linear function. True False

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

true

Step-by-step explanation:

den301095 [7]3 years ago
5 0

Answer:

true

Step-by-step explanation:

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Which description best fits the graph
soldier1979 [14.2K]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
Part A. At the local baker you can get 10 cookies for $2. How many cookies could you get for $5 dollars?
Yakvenalex [24]

Answer:

Pt. A: 25 cookies. Pt. B. $10.00

Step-by-step explanation:

1st you need to divide 10 cookies and $2 dollars, so 10/2= 5 cookies. So, it would be 5 cookies per dollar. So, then you would multiply 5 cookies*5 dollars, that equals 25. you would get 25 cookies for $5.00.  

So, for Part B, you would divide 50 cookies by $5 dollars, and that would equal $10.00.

Hope this helped you!!! (:

7 0
3 years ago
Which of the following could not be true for a function?
MatroZZZ [7]

Answer:

C) Domain is {2}, Range is {2, 3}

Step-by-step explanation:

For one value of x there are two values of y, which contradicts the definition of a function.

Definition of a function:

A function is an equation for which any x that can be plugged into the equation will yield exactly one y out of the equation.

<em>All the other options follow this definition except C</em>

3 0
3 years ago
Read 2 more answers
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
(b) Write 3*3*3*3* 3 as a single power of 3
algol13

Answer:

3⁵

Step-by-step explanation:

3×3×3×3×3=3⁵

You have a mutiplication. The base is 3, the exponent is the count of how many 3 you have. In this multiplication 3 appears 5 times, so 3⁵.

5 0
4 years ago
Read 2 more answers
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