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8090 [49]
3 years ago
6

A radio station announces one listener's name between 8:10:00 and 8:21:59 every morning. If you turn the radio on at 8:18:00, wh

at are the chances that you missed the announcement? Round your answer to the nearest hundredth.
Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

Pr = 0.67

Step-by-step explanation:

Given

Start = 8:10:00

End = 8:21:59

You = 8:18:00

Required

Chances that you missed the appointment

First, calculate the number of minutes of the radio station

n = End - Start

n = 8:21:59 - 8:10:00

n = 11\ min\ 59\ secs

Convert to seconds

n = 719

Since you turn on at 8:18:00, then you've missed the broadcast from the start till 8:18:00

So, we have:

Missed = 8:17:59 - 8:10:00

Missed = 7\ mins\ 59\ secs

Convert to seconds

Missed = 479

The probability that you missed is:

Pr = \frac{Missed}{n}

Pr = \frac{479}{719}

Pr = 0.67

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➷ If it was increased by 25% to get the new number, it would also have to be decreased by 25% to get back to the original number. Therefore, the missing number is 25

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Help with these or at least help me with how to find the percentage for number 2 idk how to find the percentage
Rama09 [41]
2/100 would be my answer
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2 years ago
How much would $500 invested at 7% interest compounded annually be
Veseljchak [2.6K]
Answer:B
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8 0
2 years ago
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How do we find a y intercept and a slope from this equation y=-1/6x+10?
wariber [46]

Answer:

Step-by-step explanation:

So all you have to do to find the slope and y intercept in that equation is look at which number is "with" the x and which is added on.

In any equation written in slope formula or y=mx+b, we can say that m = slope and b = y-intercept

So in this case we have y=-1/6x + 10

That means that m = -1/6 and b = 10

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7 0
3 years ago
Which function must have a restricted domain in order to have an inverse function?
Damm [24]

Answer:

B

Step-by-step explanation:

Consider the function f(x)=8x^2-6x+10

Rewrite it as

f(x)\\ \\=8\left(x^2-\dfrac{3}{4}x+\dfrac{5}{4}\right)\\ \\=8\left(x^2-2\cdot \dfrac{3}{8}\cdot x+\dfrac{5}{4}\right)\\ \\=8\left(x^2-2\cdot \dfrac{3}{8}\cdot x+\dfrac{9}{64}-\dfrac{9}{64}+\dfrac{5}{4}\right)\\ \\=8\left(x-\dfrac{3}{8}\right)^2+142

The domain of this function is x\in (-\infty, \infty) and the range is y\in [142,\infty)

Find the inverse function:

y-142=8\left(x-\dfrac{3}{8}\right)^2\\ \\x=\pm \sqrt{\dfrac{1}{8}(y-142)}+\dfrac{3}{8}\\ \\f^{-1}(x)= \sqrt{\dfrac{1}{8}(x-142)}+\dfrac{3}{8}

So, the domain of the inverse function is x\in [142,\infty) and the range will be \left[\dfrac{3}{8},\infty\right)

So, the domain must be restricted

7 0
3 years ago
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