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3 years ago

Can someone help me with this problem? 3[x(-6)]

Mathematics

1 answer:

Delvig [45]3 years ago

7 0

Answer:

-18x

Step-by-step explanation:

First step: remove the parentheses.

So, you'll have -3x*6.

multiply the numbers (3 x 6 = 18)

and you'll get -18x.

hope this helps!

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a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

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3 years ago

Salina, Tamara, and Uma are working on their homework together. Salina tells her friends that she got θ=52∘θ=52∘ for the inverse

svlad2 [7]

Answer:

The values reported by Uma, Salina, and Tamara are all possible values for inverse cosine

Step-by-step explanation:

Solution:-

- The solution to the inverse "cosine" problem would have a general form:

θ = cos^-1 ( a )

Where, a: Any arbitrary constant, - 1 < a < 1

- The value of θ = 52° was reported by Salina suggests that the answer lies in the first quadrant of a cartesian plane where ( sin (θ) , cos (θ) , tan (θ) ) have positive values for "a".

Hence, 0 < a < 1 , θ = 52°

- The value of θ = 128° was reported by Tamara suggests that the answer lies in the second quadrant of a cartesian plane where ( sin (θ) ) have positive values for "a" and (cos (θ) , tan (θ) have negative values for "a". So for cos (128):

Hence, -1 < a < 0 , θ = 128°

- The value of θ = 308° was reported by Uma suggests that the answer lies in the fourth quadrant of a cartesian plane where ( cos (θ) ) have positive values for "a" and (sin (θ) , tan (θ) have negative values for "a". So for cos (308):

Hence, 0 < a < 1 , θ = 308°

- The angle θ reported by Uma and Salina are similar solution because of property law of complementary angles:

cos (θ) = cos ( 360 - θ )

Where, θ = 52°, cos (52°) = cos( 308°) .. Uma and Salina conform

However, cos ( 180 - θ ) = - cos (θ)

cos(128) = - cos ( 52 ) .... Uma and Tamara conform.

5 0

3 years ago

Please can you help me??

ladessa [460]

Answer:

Why

Step-by-step explanation:

Did you report my answer ?

Did u notice u lost 40 points so then u tricked me into answering it for free ?

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