<h2>
For a = 1 and b = 10 x+1 and x+2 factors of x³-ax²-bx-8 = 0</h2><h2>
Other factor is (x-4)</h2>
Step-by-step explanation:
We have
x³-ax²-bx-8 = 0
Its factors are x+1 and x+2
That is x = -1 and x = -2 are its roots
Substituting x = -1
(-1)³-a(-1)²-b(-1)-8 = 0
-1 - a + b - 8 = 0
b - a = 9 ---------------------eqn 1
Substituting x = -2
(-2)³-a(-2)²-b(-2)-8 = 0
-8 - 4a + 2b - 8 = 0
2b - 4a = 16 ---------------------eqn 2
eqn 1 x -2
-2b + 2a = -18 ---------------------eqn 3
eqn 2 + eqn 3
-2a = -2
a = 1
Substituting in eqn 1
b - 1 = 9
b = 10
For a = 1 and b = 10, x+1 and x+2 factors of x³-ax²-bx-8 = 0
The equation is x³-x²-10x-8 = 0
Dividing with x + 1 we will get
x³-x²-10x-8 = (x+1)(x²-2x-8)
Dividing (x²-2x-8) with x + 2 we will get
x²-2x-8 = (x+2)(x-4)
So we have
x³-x²-10x-8 = (x+1)(x+2)(x-4)
Other factor is (x-4)
Answer:
The probability of scoring fewer than 5 runs when they win is P = 0.19
How to find the probability?
We know that:
The probability of winning a game is p = 0.53
The probability of scoring 5 or more runs is q = 0.59
The probability of winning and scoring 5 or more runs is k = 0.43
Notice that the joint probability is different than the product of the individual probabilities, this means that the events are not independent.
So, we know that the probability of winning is 0.53
Now, given that they win, the probability of scoring 5 or more times will be q' such that:
0.53*q' = 0.43
q' = 0.811
This means that when they win, the probability of scoring more than 5 times is 0.81
Then the probability of scoring less than 5 times when they win is 1 minus the above probability:
P = 1 - 0.81 = 0.19
The probability of scoring fewer than 5 runs when they win is P = 0.19
Answer:
no le entiendo
Step-by-step explanation:
lo siento te pido una disculpa
