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irinina [24]
3 years ago
15

∠A and \angle B∠B are vertical angles. If m\angle A=(6x-11)^{\circ}∠A=(6x−11) ∘ and m\angle B=(5x+4)^{\circ}∠B=(5x+4) ∘ , then f

ind the measure of \angle B∠B.
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer: \angle B=79^{\circ}.

Step-by-step explanation:

When two lines cross each other , then the opposite angles are known  as vertical angles.

Vertical angles are equal.

Here, ∠A and ∠B are vertical angles.

So, ∠A = ∠B

If \angle A=(6x-11)^{\circ} and \angle B=(5x+4)^{\circ}

Then , 6x-11=5x+4

Subtract 5x from both sides, we get

x-11=4

Add 11 on both sides, we get

x=15

Now , \angle B=(5(15)+4)^{\circ}=79^{\circ}

Hence, the measure of \angle B=79^{\circ}.

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Step-by-step explanation:

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6<br> The quotient of 20 and 47.
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144 = -12 (x + 5)<br><br> find x<br><br> Show work.
kumpel [21]

Answer:

-17 =x

Step-by-step explanation:

144 = -12 (x + 5)

Divide each side by -12

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7m2 + 3m + 4m2<br> What is the answer to this
mylen [45]
I’m assuming the 2’s are supposed to be exponents so you’re gonna to combine 7m^2 and 4m^2 to get 11m^2 so you’re answer would be

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8 0
3 years ago
PLEASE HELPPPPP!!!! (answer in decimal)
kakasveta [241]

Answer:

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Step-by-step explanation:

The experimental probability is the chance of an event happening based on data, or rather the experiment results, and not on a theoretical calculation. In essence, a theoretical calculation can be described by the following formula:

\frac{desired}{total}

However, the experimental probability can be described with the following formula:

\frac{number\ of\ desired\ outcomes}{number\ of \ trials}

The number of trials is the sum of the number of outcomes. In this case, the desired outcome is tails. Therefore, the experimental probability can be described using the following formula:

\frac{tails}{total}

One can also rewrite the formula as the following. This is because the total is the sum of the number of the two outcomes:

\frac{tails}{heads+tails}

Substitute,

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Simplify,

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Rewrite as a decimal:

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4 0
3 years ago
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