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3 years ago

D) Vegetable ghee is stored in a rectangular vessel of internal dimensions

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

27 vessels

Step-by-step explanation:

get the volume of the rectangular vessel 60cm ×10cm ×45cm giving you 27000cm3.Find volume of one of the cube 10cm×10cm×10cm giving 1000cm3.

if 1 cube =1000cm3

? = 27000cm3

27000cm3× 1cube

1000cm3

di

vide then get your answer as 27 vessels

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5c+ 3 < 28 or -4c-2< 14 for c.

sweet-ann [11.9K]

Answer:

c<5, and c>-4.

Steps used for answers:

5c+3<28 =

1. Subtract 3 from both sides.

5c<28-3

2. Simplify 28-3 to 25.

5c<25

3. Divide both sides by 5.

c<25/5

4. Simplify 25/5 to 5.

c<5

-----------------------

-4c-2<14 =

1. Add 2 to both sides.

-4c<14+2

2. Simplify 14+2 to 16.

-4c<16

3. Divide both sides by -4.

c>-16/4

4. Simplify 16/4 to 4.

c>−4

Done by NeighborhoodDealer

3 0

3 years ago

Read 2 more answers

Evaluate -d - euf-g if d = 5, e = -6, f = 7 and g = -9 -27 27 - 17 17

Sladkaya [172]

Answer:

You put the numbers twice, so I can't comprehend it.

Step-by-step explanation:

4 0

3 years ago

A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and

natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: $E=k\frac{q}{r^{2} }$ ; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: $p=\frac{q}{A}$ ; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: $S=4\pi r^{2}$ ; which gives us the surface of a sphere.

The inner surface: $Si=4\pi (0.06m)^{2} = 0.04 m^{2}$

The outer surface: $S=4\pi (0.08m)^{2}=0.08m^{2}$

Now we can calculate the charges,

Inner charge: $Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC$

Outer charge: $Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC$

Then, we are able to calculate both fields:

Inner field: $Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}$

Outer field: $Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}$

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0

3 years ago

Ratio of 2:3 white flour to whole wheat flour to total of 10 cups flour

LenaWriter [7]

White flour makes up 2 / (2+3) of the total 10 cups: 2/5 of the total 10 cups.

2/5 times 10 is 4 cups.

You'll need 4 cups white flour and 6 cups whole wheat flour, making a total of 10 cups of flour.

8 0

3 years ago

An astronomical unit (AU) is the average distance between Earth and the sun. One AU is equal to approximately 150,000,000 km. As

Dimas [21]

Using scientific notation, it is found that the measure of one astronomical unit in kilometers is $1.5 \times 10^8$

A number in scientific notation is given by:

$a \times 10^b$

In which $a \in [1, 10)$

To realize the conversion from decimal to scientific notation, b is the number of decimal places the comma moves, being positive if to the left, negative if to the right.

In this problem, 1 AU = 150,000,000 km.

The comma has to move 8 places to the right, hence $b = 8$

Then, the measure is: $1.5 \times 10^8$

For more on scientific notation, you can check brainly.com/question/16394306

5 0

2 years ago