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Marina86 [1]
4 years ago
14

Cot^2x csc^2x + 2 csc^2x –cot^2 = 2

Mathematics
1 answer:
kow [346]4 years ago
4 0

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

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Answer:

m∠B = 157°

Step-by-step explanation:

Cyclic quadrilateral is the quadrilateral whose vertices lie on the edge of the circle

In the cyclic quadrilateral each two opposite angles are supplementary (the sum of their measures is 180°)

∵ Quadrilateral ABCD is inscribed in a circle

- That means its four vertices lie on the edge of the circle

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<em>Each two opposite angles in the cyclic quadrilateral are supplementary (The sum of their measures is 180°)</em>

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