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Furkat [3]
2 years ago
5

Luella has a pond in her yard. She wants to surround it with 330 feet of fencing. Fencing is sold by the yard. How many yards sh

ould she buy?​
Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
4 0

Answer:

110 yards

330/ 3 ,=110

1yard =3 feet

Step-by-step explanation:

if you multiply 3 to 110=330

or 330 divided by 3=110 yards.

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5x−6=3x+10 PLSPLS HELP
vichka [17]

Answer:

x = 8

Step-by-step explanation:

Let's solve your equation step-by-step.

5x−6=3x+10

Step 1: Subtract 3x from both sides.

5x−6−3x=3x+10−3x

2x−6=10

Step 2: Add 6 to both sides.

2x−6+6=10+6

2x=16

Step 3: Divide both sides by 2.

2x /2 = 16/ 2

x=8

3 0
3 years ago
Read 2 more answers
Tony's recipe for soup calls for 11/4 teaspoons of salt. He wants to use 1/2 that
mart [117]

Answer:

11/8

Step-by-step explanation:

Simplify 11/4 = 2 3/4

half of 2 = 1

half of 3/4 = 3/8

1 3/8 changed to an inproper fraction = 11/8

8 0
3 years ago
in a class of 30 students the highest score in physics test was 98 and the lowest was 35 what was the range?​
In-s [12.5K]

Answer:

63

Step-by-step explanation:

basta ayon sagot ko obob ko eh

5 0
3 years ago
How do you do 3 through 4
Furkat [3]

#3 is not a function because there are two answers for one out put

#4 is a function because it is a straight line

8 0
3 years ago
Which is the solution set to the inequality (4x-3)(2x-1)&gt=0?
Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0         2x - 1 = 0

x = \frac{3}{4}               x = \frac{1}{2}

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------\frac{1}{2}------\frac{5}{8}------\frac{3}{4}------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1]  = ( - )( - ) = +  THIS WORKS!

Test Point \frac{5}{8}: [4(\frac{5}{8}) - 3][2(\frac{5}{8}) - 1]  = ( - )( + ) = -  <em>This does NOT work</em>

Test Point 1: [4(1) - 3][2(1) - 1]  = ( + )( + ) = +  THIS WORKS!

Answer: x ≤ \frac{1}{2}   or   x ≥ \frac{3}{4}

Interval Notation: (-∞, \frac{1}{2}] U [\frac{3}{4}, ∞)

Graph: ←------\frac{1}{2}          \frac{3}{4}--------→

5 0
3 years ago
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