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ololo11 [35]
3 years ago
13

Need helpwith these problems​

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0

Answer:

answer is c, e, and a

Step-by-step explanation:

:-)

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1. Write a ratio and a percent for the shaded area. (1 point)
Kipish [7]

Answer:

3/10, 30%

Step-by-step explanation:

the shaded region is 9/30 which is equivilent to 3/10 and 3/10is 30 percent.

hope this helps!

8 0
3 years ago
Help Me On These Please
RoseWind [281]
#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term

#2 has zero like terms. 15 has no variable, and the other terms have different variables.

#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.

#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
7 0
3 years ago
15+9=?(5+3) please help
Tema [17]

Answer:

3

because 15 + 9 = 24

and 3(5 + 3) which is 3 * 5 + 3 * 3 = 15 + 9 = 24

= 24 = 24

Step-by-step explanation:

Please mark me as the brainliest

3 0
4 years ago
CAN SOMEONE PLS ANSWER THIS QUESTION FAST<br> I WILL MARK BRAINLIEST
Yakvenalex [24]

Answer:

B 5

Step-by-step explanation:

it is the same ratio as the red

8 0
2 years ago
Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

5 0
3 years ago
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