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2 years ago

Which of the ten basic functions in

Mathematics

1 answer:

storchak [24]2 years ago

8 0

Step-by-step explanation:

Which of the ten basic functions in

our toolkit have an infinite number of

local extrema?

a) cos(x), 2

b) sin(x), cos(x)

c) In(x), cos(x)

d) sin(x), x2

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There are 267 students and 21 adults going on a field trip an equal number of people will ride on each bus there are 9 buses how

DiKsa [7]

Answer:

The number of people on each bus is 32

Step-by-step explanation:

We are given

Total number of students =267

Total number of adults =21

So,

Total number of passengers = ( Total number of students)+(Total number of adults)

now, we can plug values

Total number of passengers =267+21

Total number of passengers =288

We are given

Number of buses=9

so,

Number of passengers on each bus = (total number of passengers)/( Number of buses)

now, we can plug values

Number of passengers on each bus is

$=\frac{288}{9}$

$=32$

So,

The number of people on each bus is 32

6 0

3 years ago

A car rental company has 2 rental plans. plan A charges $49 per day. plan B charges $25 per day, plus $.10 per mile. how many mi

suter [353]

$49 > 25 + .10x$

3 0

4 years ago

15 yard gain in integer

Furkat [3]

Answer:

+ 15 is the integer measure.

Step-by-step explanation:

We have given yard that means the length since, yard is unit measure.

Integer are those numbers which do not have fractional part.

They are not in the form of rational number that is not in the form of $\frac{p}{q}$

Yard is a unit of linear measure.

Yard is equal to 3 feets.

4 0

3 years ago

How do you simplify this expression with an answer in positive exponential notation? Please provide the process. Thank you!

Otrada [13]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\ -------------------------------\\\\ 8^{-2}\cdot \cfrac{3^0-8^{-3}}{4^{-5}}\implies 8^{-2}\cdot \cfrac{1-\frac{1}{8^3}}{\frac{1}{4^5}}\implies 8^{-2}\cdot \cfrac{1-\frac{1}{(2^3)^3}}{\frac{1}{(2^2)^5}}$

$\bf 8^{-2}\cdot \cfrac{\quad \frac{512-1}{2^9}\quad }{\frac{1}{2^{10}}}\implies (2^3)^{-2}\cdot \cfrac{\quad \frac{511}{2^9}\quad }{\frac{1}{2^{10}}}\implies 2^{-6}\cdot \cfrac{511}{2^9}\cdot \cfrac{2^{10}}{1} \\\\\\ 2^{-6}\cdot \cfrac{511\cdot 2^{10}}{2^9}\implies 2^{-6}\cdot 511\cdot 2^{10}\cdot 2^{-9}\implies 2^{-6}\cdot 511\cdot 2^{10-9} \\\\\\ 2^{-6}\cdot 511\cdot 2\implies 511\cdot 2^{-6}\cdot 2\implies 511\cdot 2^{-6+1}\implies 511\cdot 2^{-5} \\\\\\ 511\cdot \cfrac{1}{2^5}\implies \cfrac{511}{32}$

4 0

4 years ago

Determine if the data comes from a linear function or an exponential function. Then, enter

svet-max [94.6K]

1. The data is not linear. There's not a constant difference between the f(x) values. (AKA there's not a fixed slope between the data points)

2. The data is exponential, because there's a consistent ratio in the f(x) values:

189/567 = 1/3

63/189 = 1/3

21/63 = 1/3

7/21 = 1/3

Each new y-value (aka f(x)-value) is 1/3 the previous value.

Also, f(0)=567.

If we put that together, we have f(x) = 567 (1/3)^x.

8 0

3 years ago