Answer:
make me the branliest the answer is C
Step-by-step explanation:
Pool X has 1200 gallons of water in it. It is being drained at a rate of 15 gallons per minute. If lowercase x is the number of minutes, then it has 1200-15x gallons left in the pool.
Consider after 1 minute we have x = 1, so,
1200-15x = 1200-15*1 = 1200-15 = 11185
Then after 2 minutes we have x = 2, which means,
1200-15x = 1200-15*2 = 1200-30 = 11170
is the amount left over in gallons.
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In contrast, Pool Y is empty and we add 25 gallons per minute. So we start with 0 and add on 25x getting 0+25x = 25x as the expression representing the amount of gallons of water in Pool Y
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So we found these two expressions
1200-15x
25x
to represent the amount of water (in gallons) for Pool X and Pool Y respectively.
We want to know when Pool Y will have more water. So we get to this final answer
1200 - 15x < 25x
It is in the form A < B, where A is the amount of water in Pool X and B is the amount of water in Pool Y.
X=27
81 = 3x= 27
So x means 27
Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4
Therefore, the system has infinite number of solutions.
yes i agree because if all the integers are positive, the answer stays positive which means if you know your integer rules: a positive divide by a positive it stays positive. its the same thing for all the other operations. hope this helps.
