74 R28
So sorry if its incorrect!
You solve an equation like this by adding the opposite of the constant to both sides of the equation.
... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b
... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0
... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V
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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.
Take the picture clearly because I can’t read nothing
Answer:
Step-by-step explanation:
surface area of sphere=a
4pir^2=a
r^2=a/4p
r=root(a/4pi)
if radius is doubled
r1=2root(a/4pi)
r1^2=4(a/4pi)
a/a1=(4pia/4pi)/(4pi 4a/4pi)=1/4
so a is increased by 4 times
