The length of the DEFG rectangle
is 6/4 of the length of the ABCD rectangle.
6/4=3/2 = 1,5
How many times greater than the surface of ABCD is the DEFG area?
1,5 times
Answer:
L = 14/
<u>OR</u> 9.899
Step-by-step explanation:
cos(angle) = adjacent/ hypotenuse
hypotenuse = length of ladder
adjacent = 7 feet
length of ladder = L
1/L = cos(45)/7
L = 7/cos(45)
<u><em>MAKE SURE CALCULATOR IS IN DEGREE MODE</em></u>
L = 7/(
/2)
L = 14/
Answer:
0.03125
Step-by-step explanation:
In fraction form i got 1/32. Hope this helps a little bit!
Answer:
20, 250
Step-by-step explanation:
just search up surface area of a square pyramid, enter the width, length, and height and it should give you: 20,250
