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Jlenok [28]
2 years ago
12

Math is so hard too me help​

Mathematics
2 answers:
Mandarinka [93]2 years ago
7 0

Answer:

Its c pretty sure

jarptica [38.1K]2 years ago
4 0

The answer to your question is D

First, you multiply the two decimal numbers, without the x 10 part:

3.84 x 2

7.68

Next, you add the exponents of the 10's:

5 + 6

11

Therefore, it is 7.68 x 10^11

Hope it helps and have a great day!

You might be interested in
I really need help! it’s due soon:)
Stells [14]

Answer:

(5, 5), (7, 2), (3, 2)

Step-by-step explanation:

When reflecting a figure across the y-axis, the x value will be the opposite and the y value will remain the same

reflection across y-axis:

(x, y) ---> (-x, y)

Hope this helps!!

7 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
1-07 What is the length of the marked portion of each line segment? Copy the
VikaD [51]

Answer:

A. 25 B. 45 C. 30

Step-by-step explanation:

A.

75 ÷ 3 = 25

25 × 1 = 25

B.

75 ÷ 5 = 15

15 × 3 = 45

C.

50 ÷ 5 = 10

10 × 3 = 30

5 0
2 years ago
A circle has a circumference of 907.46907.46 units. What is the diameter of the circle?
astra-53 [7]

question is wrong sir

there is no any value with two points

6 0
3 years ago
Please help me solve this 5^2x=7^x+1
denis23 [38]

Answer:

x=\frac{ln7}{2ln5-ln7}

Step-by-step explanation:

5^2x=7^x+1 ⇔ ln5^2x = ln7^x+1 ⇔ 2xln5 = (x+1)ln7 ⇔ (2ln5-ln7)x = ln7

⇔ x = ln7/(2ln5-ln7)

7 0
3 years ago
Read 2 more answers
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