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3 years ago

Please help me! Will give brainlst :)

Mathematics

2 answers:

4vir4ik [10]3 years ago

8 0

Answer:

y = 1/2

x = -3/2

Step-by-step explanation:

y = 3x+5

Substance instances of y in the equation.

x + 3x +5 = -1

4x=-6

x= -6/4

y = 1/2

kotegsom [21]3 years ago

3 0

3x-5 is the answeeeerrrrr

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NEED STEP BY STEP WORK HIGH POINTS

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Answer:

The awnser is 16 times 2

equals 32

Step-by-step explanation:

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3 years ago

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A promissory note for $3600.00 dated May 15, 2012, requires an interest payment of $370.00 at maturity. If interest is at 9.6% c

vladimir1956 [14]

The due date of the promissory note is May 24th 2013.

Data;

Present Value (PV) = $3600
Interest = $370
Future Value (FV) = PV + I = $3600 + $370 = $3970

To calculate the due date of the note, we can use the formula of future value of the note.

$FV = PV (1 + \frac{r}{n})^d\\ 3970 = 3600 (1 + \frac{9.6}{12})^d\\3970 = 3600(1+0.008)^d\\\frac{3970}{3600} =(1.008)^n$

Let's take the natural log of both sides

$(1.008)^n = (\frac{3970}{3600})\\ n\ln(1.008) = \ln(\frac{397}{360})\\ n = 12.28$

This is approximately 12 months and 9 days.

The due date of the promissory note is May 24th 2013.

Learn more on promissory note here;

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2 years ago

(06.01)The probability that an event will occur is 95%. Which of these best describes the likelihood of the event occurring? Lik

Elan Coil [88]

Answer:

Likely

Step-by-step explanation:

The probability of occurrence of a certain event Given as 95% has a high probability figure and hence such event is LIKELY to occur. We cannot class this probability percentage as certain because, an event which is certain to occur who'll have a probability percentage of 100% or a value of 1. Therefore, a probability percentage of 95% occurrence still has 5% Chace of not happening, hence it is only very likely to occur. Hence, the phrase which best describes the probability of an event with 95% probability happening is LIKELY.

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3 years ago

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Mars2501 [29]

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Then,

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For $v(0)=v_0$ , then

$v(0)=-kv^2(0)+c=v_0 \\ \\ \Rightarrow c=v_0$

Thus, $v(t)=-kv(t)^2t+v_0$

For $v(t)= \frac{1}{2} v_0$ , we have

$\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\ \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\ \\ \Rightarrow kv_0t=2 \\ \\ \Rightarrow t= \frac{2}{kv_0}$

Part B

Recall that from part A,

$v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\ \\ \Rightarrow dx=-kv^2tdt+v_0dt \\ \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\ \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a$

Now, at initial position, t = 0 and $v=v_0$ , thus we have

$x=a$

and when the velocity drops to half its value, $v= \frac{1}{2} v_0$ and $t= \frac{2}{kv_0}$

Thus,

$x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\ \\ =- \frac{1}{2k} + \frac{2}{k} +a$

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

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3 years ago

Graph the inequality y+4<-2(×+4)

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$y + 4 < - 2(x + 4) \\ \\ 1. \: - \frac{y + 4}{2} > x + 4 \\ 2. \: - \frac{y + 4}{2} - 4 > x \\ 3. \: x < - \frac{y + 4}{2} - 4$

number 3 is your answer x<-y+4/2-4

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3 years ago