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Lapatulllka [165]
3 years ago
15

A right triangle has a hypotenuse of length 10 meters. One leg is 6 meters long. What is the length of the other leg of the tria

ngle?
A. 4 m

B. v8

C. v136

D. 8 m
Mathematics
2 answers:
timama [110]3 years ago
7 0
D because the two sides have to be larger than the hypotenuse when added
Snowcat [4.5K]3 years ago
4 0

Answer:

D) 8 meters

Step-by-step explanation:

You must use the pythagorean theorem

The hypotenuse (or <em>c</em>) is 10

<em>a </em>is 6

10^{2} -6^{2} =64

\sqrt{64} = 8

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What is the slope of a line perpendicular to<br><br> y =3/4 x+2
Irina18 [472]

Answer:

-3/4 slope

Step-by-step explanation:

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6 0
3 years ago
Which expressions are equivalent
PolarNik [594]

Answer:

Options (B) and (C)

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The given expression is (d^{\frac{1}{8}})^5

By simplifying this expression,

(d^{\frac{1}{8}})^5

= (\sqrt[8]{d})^{5}

Option (B)

Similarly,

(d^{\frac{1}{8}})^5

= d^{\frac{5}{8}}

= (d^{5})^{\frac{1}{8}}

Option (C)

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5 0
3 years ago
PLEASE HELP I REALLY APPRECIATE IT AND NEED IT.
Oksanka [162]

Problem 5

Each two tangents form a right angle from the center of the circle to the circumference (a radius) and from the circumference to the exterior point. That makes a kite of 2 tangents and 2 radii.

The radii make an angle of 360 - 2*90 - 47 = 133.

That is also the central angle for the arc you are asking about.

Answer: 133.

Problem 9

The center is at point (-6, - 8) So far what you have is

(x + 6)^2 + (y + 8)^2 = r^2

You use the two given points to find r^2

r^2 = (x2 - x1)^2 + (y2 - y1)^2

r^2 = (-6 - 0)^2 + (- 8 - 0)^2

r^2 = 36 + 64

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The circles equation is (x + 6)^2 + (y + 8)^2 = 100

Answer D

7 0
3 years ago
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