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padilas [110]
3 years ago
13

For what value of x do the expressions 2x +3 and 3x -6 have the same value?

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
6 0

Answer:

9

Step-by-step explanation:

2x+3=3x-6

3+6=3x-2x

9=x

SVEN [57.7K]3 years ago
5 0

Answer:

x=  9

Step-by-step explanation:

hello :

2x +3 = 3x -6

2x-3x=-6-3

-x= -9

so : x=  9

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Deshawn draws a regular pentagon and rotates it about its center.
salantis [7]

Answer:

f

Step-by-step explanation:

7 0
3 years ago
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The following table shows the assets and liabilities of the Smith family in 2005 and 2009.
Marrrta [24]
2005: 
Asset = 200,000 + 25,000 = 225,000
Liability = 30,000 + 8,000 = 38,000

2009
Asset = 180,000 + 18,000 + 20,000 = 218,000
Liability  = 18,000 + 5,000 = 23,000

Assets decreased by 7,000. From 225,000 to 218,000
Liabilities decreased by 13,000. From 38,000 to 23,000

<span>a. From 2005 to 2009, both assets and liabilities decreased. </span>
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3 years ago
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A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
Andre picks blocks out of a bag 60 times and notes that 43 of them were green. What should Andre estimate for the probability of
kiruha [24]

43/60 would be the probability

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Find the supplement of an angle that measures 20 degrees.
OLEGan [10]
Supplementary angles add to be 180 degrees. If one angle is 20. The supplement angle is 160.
180 - 20 = 160
160 is your answer.
8 0
2 years ago
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