The <em>total</em> area of all six faces of the tunnel is
square centimeters.
<h2>Procedure - Surface area of a tunnel for a toy train</h2>
The surface area of the solid (
) used to represent the tunnel for a toy train is the sum of its six faces (two <em>semicircular</em> sections, inner <em>semicircular</em> arc section, outer <em>semicircular</em> arc section, two rectangles).
<h3>Determination of the surface area of the tunnel based on information of the diagram</h3>
We calculate the surface area as following:
![A = 2\cdot \frac{\pi}{2} \cdot [(10\,cm)^{2}-(8\,cm)^{2}] + \pi\cdot (8\,cm)\cdot (30\,cm) + \pi\cdot (10\,cm)\cdot (30\,cm) + 2\cdot (2\,cm)\cdot (30\,cm)](https://tex.z-dn.net/?f=A%20%3D%202%5Ccdot%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%5Ccdot%20%5B%2810%5C%2Ccm%29%5E%7B2%7D-%288%5C%2Ccm%29%5E%7B2%7D%5D%20%2B%20%5Cpi%5Ccdot%20%288%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29%20%2B%20%5Cpi%5Ccdot%20%2810%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29%20%2B%202%5Ccdot%20%282%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29)

The <em>total</em> area of all six faces of the tunnel is
square centimeters. 
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Answer:
31.74 million people were employed.
Step-by-step explanation:
The unemployment rate is the number of unemployed people divided by the size of the labor force.
So the first step to solve this problem is finding the size of the country's labor force.
Suppose some country had an adult population of about 46 million, a labor-force participation rate of 75 percent.
So the size of the country labor force is:
0.75 * 46 million = 34.5 million people.
Unemployment rate of 8 percent. How many people were employed?
This means that 100 - 8 = 92 percent of people were employed. Remembering, this considers only the labor force, of 34.5 million people. So
0.92 * 34.5 million = 31.74 million
31.74 million people were employed.
Answer:
E) -4,7 and -2,8
Step-by-step explanation:
parallel lines have same slope
x - 2y = 16
y = 1/2 x -8 slope: 1/2
E. slope = Δy / Δx = (8-7) / (-2 - -4) = 1/2
Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Answer:
Share of A is $116 and Share of B is $84.
Step-by-step explanation:
Let the share of A be 
Let the share of B be 
Given:
$200 is shared between A and B
So, 
Also given;
twice of A's share is less than 3 times than B's share by $20

Solution:
Now multiplying equation 1 by 3 we get,

Now Adding equation 2 and equation 3 we get

Now Substituting the value of x in equation 1 we get,

Hence, Share of A is $116 and Share of B is $84.