Question

A painter is painting a rectangular wall that measures 23.6 ft by 19.2 ft. Each gallon can of paint covers 200 square feet. What are the fewest gallons needed to paint the wall?

Answer 1

Answer:

3 gallons

Step-by-step explanation:

Length of the rectangular wall = 23.6 feet

Width of the rectangular wall = 19.2 feet

Surface area of the wall = 23.6 × 19.2

                                        = 453.12 square feet

∵ 200 square feet of the wall is covered by the amount of paint = 1 gallon

∴ 1 square feet of the wall will be covered by the amount of paint = $\frac{1}{200}$ gallons

∴ 453.12 square feet will require the amount of paint = $\frac{453.12}{200}$

                                                                                         = 2.2656 gallons

Therefore, minimum 3 gallons will be required to paint the wall.