Answer:
C.
Step-by-step explanation:
The eqn. of a circle with centre (h,k)and radius ris given by,
Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.
<span>In this case, that would be 13,000.</span>
Answer:
3x+0.3=3.3.
\ /
We move all terms to the left:
3x+0.3-(3.3.)=0
We add all the numbers together, and all the variables
3x+0.3-0=0
We add all the numbers together, and all the variables
3x+0.3=0
We move all terms containing x to the left, all other terms to the right
3x=-0.3
x=-0.3/3
x=-0.3/3
/ \
*eliza*