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3 years ago

3.56 gallons of milk is sold for $12.12. If you have $22.13 in your wallet. How many

Mathematics

1 answer:

olga_2 [115]3 years ago

6 0

Answer:

<h2>6.5 gallons</h2>

Step-by-step explanation:

3.56 gallons of milk is sold for $12.12. If you have $22.13 in your wallet.

find:

How many gallons of milk you can buy?

solution:

<u> $12.12 </u> = $3.404 per gal. of milk.

3.56 gal. of milk

<u> $22.13 </u> = 6.5 gallons of milk

$3.404 per gal. of milk.

therefore, you can buy 6.5 gallons of milk with $22.13

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If x-5(x-7)=-7 then x equals what?

NeX [460]

Expand

simplify x - 5x + 35 to -4x + 35

subtract 35 from both sides

simplify -7 - 35 to -42

divide both sides by -4

two negatives make a positive

simplify 42/4 to 21/2

Answer: x = 21/2.

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2 years ago

The function f(x) = 2x2 + 2 represents the rate of a bus traveling in miles per hour. The function g(x) = x + 2 represents the t

AlekseyPX

Answer:

(f • g)(3) = 100, the distance in miles the bus traveled

Step-by-step explanation:

The product of (miles/hour) and (hours) is (miles), so only answers with units of distance are applicable. The numbers are ...

f(3) = 2·3² +2 = 20 . . . . miles per hour

g(3) = 3+2 = 5 . . . . hours

so (f·g)(3) = f(3)·g(3) = 20·5 = 100 . . . . miles

This means only the first answer choice is applicable.

6 0

3 years ago

Read 2 more answers

8. Caitlyn wants to build a fence around her flower garden,

ioda

Answer:

Step-by-step explanation:

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2 years ago

Which of the following is a binomial? <br>A) 8x^5<br>B) 11x+18 <br>C) 14x^2+5x+12 <br>D) 4/x

Citrus2011 [14]

A Binomial is a Polynomial with two terms:

8 0

1 year ago

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

= 0.01153 computers

6 0

3 years ago