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Advocard [28]
3 years ago
13

3. What is the range of the quadratic function shown on the graph below? ده ستA:

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0
Because of the symmetry of the parabola, its stationary point will always be in the middle of its x-intercepts (or zeroes). ...
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If f(x) = -x^2 + 6x - 1 and g(x) = 3x^2 - 4x - 1, find (f + g)(x).
Alenkinab [10]

f(x)=-x^2+6x-1 \\g(x)=3x^2-4x-1 \\f(x)+g(x)=-x^2+6x-1+3x^2-4x-1=\boxed{2x^2+2x-2}

The answer is A.

Hope this helps.

r3t40

5 0
3 years ago
What is the solution to this equation?
solong [7]

Answer:

4x=32

or,x=32/4

therefore,x=8

8 0
3 years ago
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What’s the correct answer for this question?
Maurinko [17]

Answer:

B

Step-by-step explanation:

I put the answer in an atachement

3 0
3 years ago
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What is the value of 6x^2-4x when x=5
creativ13 [48]
This answer is 678. 0003. 9
4 0
3 years ago
Plzzz help don’t understand plz explain
kherson [118]

So the easiest way to do this problem is to put your equation in linear form, meaning y = the rest of the equation.

I'm going to show the work to do that below:

2x - y = 4

-2x -2x (Here I am subtracting 2x)

- y = 4 - 2x

(-1)(- y) = (-1)(4 - 2x) (Now I'm multiplying both sides by -1 to make y positive)

y = 2x - 4 (And just for neat purposes I'm going to put the 2x in front of the 4)

Now you have your equation ( y=2x-4 ) and you're ready to put it on the points of your graph.

Start on the point (0, -4) to represent the y axis.

y = 2x - 4

Then, your rise (2) over your run (1)

so your coordinates for a line will be:

(0, -4) (-2, 1) (1, 0)

You only need to plot these three to connect your line.

I appologize for my lack of visuals i understand this might be confusing, however if you have any further questions feel free to let me know!

8 0
4 years ago
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